+/*
+ * _________________________________________________________________ */
+
+static inline int mb_buddy_adjust_border(int* bit, void* bitmap, int side)
+{
+ if (mb_test_bit(*bit + side, bitmap)) {
+ mb_clear_bit(*bit, bitmap);
+ (*bit) -= side;
+ return 1;
+ }
+ else {
+ (*bit) += side;
+ mb_set_bit(*bit, bitmap);
+ return -1;
+ }
+}
+
+static void mb_buddy_mark_free(struct ext4_buddy *e4b, int first, int last)
+{
+ int max;
+ int order = 1;
+ void *buddy = mb_find_buddy(e4b, order, &max);
+
+ while (buddy) {
+ void *buddy2;
+
+ /* Bits in range [first; last] are known to be set since
+ * corresponding blocks were allocated. Bits in range
+ * (first; last) will stay set because they form buddies on
+ * upper layer. We just deal with borders if they don't
+ * align with upper layer and then go up.
+ * Releasing entire group is all about clearing
+ * single bit of highest order buddy.
+ */
+
+ /* Example:
+ * ---------------------------------
+ * | 1 | 1 | 1 | 1 |
+ * ---------------------------------
+ * | 0 | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
+ * ---------------------------------
+ * 0 1 2 3 4 5 6 7
+ * \_____________________/
+ *
+ * Neither [1] nor [6] is aligned to above layer.
+ * Left neighbour [0] is free, so mark it busy,
+ * decrease bb_counters and extend range to
+ * [0; 6]
+ * Right neighbour [7] is busy. It can't be coaleasced with [6], so
+ * mark [6] free, increase bb_counters and shrink range to
+ * [0; 5].
+ * Then shift range to [0; 2], go up and do the same.
+ */
+
+
+ if (first & 1)
+ e4b->bd_info->bb_counters[order] += mb_buddy_adjust_border(&first, buddy, -1);
+ if (!(last & 1))
+ e4b->bd_info->bb_counters[order] += mb_buddy_adjust_border(&last, buddy, 1);
+ if (first > last)
+ break;
+ order++;
+
+ if (first == last || !(buddy2 = mb_find_buddy(e4b, order, &max))) {
+ mb_clear_bits(buddy, first, last - first + 1);
+ e4b->bd_info->bb_counters[order - 1] += last - first + 1;
+ break;
+ }
+ first >>= 1;
+ last >>= 1;
+ buddy = buddy2;
+ }
+}
+